-4.9x^2+17x+0.6=2

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Solution for -4.9x^2+17x+0.6=2 equation:



-4.9x^2+17x+0.6=2
We move all terms to the left:
-4.9x^2+17x+0.6-(2)=0
We add all the numbers together, and all the variables
-4.9x^2+17x-1.4=0
a = -4.9; b = 17; c = -1.4;
Δ = b2-4ac
Δ = 172-4·(-4.9)·(-1.4)
Δ = 261.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{261.56}}{2*-4.9}=\frac{-17-\sqrt{261.56}}{-9.8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{261.56}}{2*-4.9}=\frac{-17+\sqrt{261.56}}{-9.8} $

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